3j^2+22j+7=

Solution for 3j^2+22j+7= equation:

Simplifying
3j2 + 22j + 7 = 0

Reorder the terms:
7 + 22j + 3j2 = 0

Solving
7 + 22j + 3j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(7 + j)(1 + 3j) = 0

Subproblem 1
Set the factor '(7 + j)' equal to zero and attempt to solve:

Simplifying
7 + j = 0

Solving
7 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + j = 0 + -7

Combine like terms: 7 + -7 = 0
0 + j = 0 + -7
j = 0 + -7

Combine like terms: 0 + -7 = -7
j = -7

Simplifying
j = -7
Subproblem 2
Set the factor '(1 + 3j)' equal to zero and attempt to solve:

Simplifying
1 + 3j = 0

Solving
1 + 3j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3j = 0 + -1
3j = 0 + -1

Combine like terms: 0 + -1 = -1
3j = -1

Divide each side by '3'.
j = -0.3333333333

Simplifying
j = -0.3333333333
Solution
j = {-7, -0.3333333333}